2[4x-4(y-2)]=

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Solution for 2[4x-4(y-2)]= equation:


Simplifying
2[4x + -4(y + -2)] = 0

Reorder the terms:
2[4x + -4(-2 + y)] = 0
2[4x + (-2 * -4 + y * -4)] = 0
2[4x + (8 + -4y)] = 0

Reorder the terms:
2[8 + 4x + -4y] = 0
[8 * 2 + 4x * 2 + -4y * 2] = 0
[16 + 8x + -8y] = 0

Solving
16 + 8x + -8y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + 8x + -16 + -8y = 0 + -16

Reorder the terms:
16 + -16 + 8x + -8y = 0 + -16

Combine like terms: 16 + -16 = 0
0 + 8x + -8y = 0 + -16
8x + -8y = 0 + -16

Combine like terms: 0 + -16 = -16
8x + -8y = -16

Add '8y' to each side of the equation.
8x + -8y + 8y = -16 + 8y

Combine like terms: -8y + 8y = 0
8x + 0 = -16 + 8y
8x = -16 + 8y

Divide each side by '8'.
x = -2 + y

Simplifying
x = -2 + y

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